At a certain depth "d" below surfac | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{ GM }{ R ^2}\left[1-\frac{ d }{ R }ight]=\frac{4 	imes GM }{(4 R )^2}$

$1-\frac{ d }{ R }=\frac{1}{4} \Rightarrow \frac{ d }{ R }=\frac{3

Vedclass · Accepted Answer

$4800$

Vedclass · Answer

$\frac{ GM }{ R ^2}\left[1-\frac{ d }{ R }ight]=\frac{4 	imes GM }{(4 R )^2}$

$1-\frac{ d }{ R }=\frac{1}{4} \Rightarrow \frac{ d }{ R }=\frac{3}{4} \Rightarrow d \frac{3}{4} R$

$d =4800\,km$

At a certain depth "$d$" below surface of earth. value of acceleration due to gravity becomes four times that of its value at a height $3\,R$ above earth surface. Where $R$ is Radius of earth (Take $R =6400\,km$ ). The depth $d$ is equal to $............\,km$

Similar Questions

Assuming the earth to be a sphere of uniform density, the acceleration due to gravity inside the earth at a distance of $r$ from the centre is proportional to

An iron ball and a wooden ball of the same radius are released from a height $‘h’$ in vacuum. The time taken by both of them to reach the ground is

If the density of the earth is doubled keeping its radius constant then acceleration due to gravity will be........ $m/{s^2}$ . $(g = 9.8\,m/{s^2})$

What will be the formula of mass of the earth in terms of $g, R$ and $G$ ?

Where will it be profitable to purchase $1$ kilogram sugar